Optimal. Leaf size=150 \[ -\frac{c \left (a+\frac{b}{x}\right )^{n+1} (a c-b d (1-n)) \, _2F_1\left (1,n+1;n+2;\frac{c \left (a+\frac{b}{x}\right )}{a c-b d}\right )}{d^2 (n+1) (a c-b d)^2}-\frac{c \left (a+\frac{b}{x}\right )^{n+1}}{d \left (\frac{c}{x}+d\right ) (a c-b d)}+\frac{\left (a+\frac{b}{x}\right )^{n+1} \, _2F_1\left (1,n+1;n+2;\frac{b}{a x}+1\right )}{a d^2 (n+1)} \]
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Rubi [A] time = 0.11531, antiderivative size = 150, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {514, 446, 103, 156, 65, 68} \[ -\frac{c \left (a+\frac{b}{x}\right )^{n+1} (a c-b d (1-n)) \, _2F_1\left (1,n+1;n+2;\frac{c \left (a+\frac{b}{x}\right )}{a c-b d}\right )}{d^2 (n+1) (a c-b d)^2}-\frac{c \left (a+\frac{b}{x}\right )^{n+1}}{d \left (\frac{c}{x}+d\right ) (a c-b d)}+\frac{\left (a+\frac{b}{x}\right )^{n+1} \, _2F_1\left (1,n+1;n+2;\frac{b}{a x}+1\right )}{a d^2 (n+1)} \]
Antiderivative was successfully verified.
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Rule 514
Rule 446
Rule 103
Rule 156
Rule 65
Rule 68
Rubi steps
\begin{align*} \int \frac{\left (a+\frac{b}{x}\right )^n x}{(c+d x)^2} \, dx &=\int \frac{\left (a+\frac{b}{x}\right )^n}{\left (d+\frac{c}{x}\right )^2 x} \, dx\\ &=-\operatorname{Subst}\left (\int \frac{(a+b x)^n}{x (d+c x)^2} \, dx,x,\frac{1}{x}\right )\\ &=-\frac{c \left (a+\frac{b}{x}\right )^{1+n}}{d (a c-b d) \left (d+\frac{c}{x}\right )}-\frac{\operatorname{Subst}\left (\int \frac{(a+b x)^n (a c-b d-b c n x)}{x (d+c x)} \, dx,x,\frac{1}{x}\right )}{d (a c-b d)}\\ &=-\frac{c \left (a+\frac{b}{x}\right )^{1+n}}{d (a c-b d) \left (d+\frac{c}{x}\right )}-\frac{\operatorname{Subst}\left (\int \frac{(a+b x)^n}{x} \, dx,x,\frac{1}{x}\right )}{d^2}+\frac{(c (a c-b d (1-n))) \operatorname{Subst}\left (\int \frac{(a+b x)^n}{d+c x} \, dx,x,\frac{1}{x}\right )}{d^2 (a c-b d)}\\ &=-\frac{c \left (a+\frac{b}{x}\right )^{1+n}}{d (a c-b d) \left (d+\frac{c}{x}\right )}-\frac{c (a c-b d (1-n)) \left (a+\frac{b}{x}\right )^{1+n} \, _2F_1\left (1,1+n;2+n;\frac{c \left (a+\frac{b}{x}\right )}{a c-b d}\right )}{d^2 (a c-b d)^2 (1+n)}+\frac{\left (a+\frac{b}{x}\right )^{1+n} \, _2F_1\left (1,1+n;2+n;1+\frac{b}{a x}\right )}{a d^2 (1+n)}\\ \end{align*}
Mathematica [A] time = 0.109819, size = 120, normalized size = 0.8 \[ \frac{\left (a+\frac{b}{x}\right )^{n+1} \left (-\frac{c (a c+b d (n-1)) \, _2F_1\left (1,n+1;n+2;\frac{c \left (a+\frac{b}{x}\right )}{a c-b d}\right )}{(n+1) (a c-b d)^2}-\frac{c d x}{(c+d x) (a c-b d)}+\frac{\, _2F_1\left (1,n+1;n+2;\frac{b}{a x}+1\right )}{a (n+1)}\right )}{d^2} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.507, size = 0, normalized size = 0. \begin{align*} \int{\frac{x}{ \left ( dx+c \right ) ^{2}} \left ( a+{\frac{b}{x}} \right ) ^{n}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a + \frac{b}{x}\right )}^{n} x}{{\left (d x + c\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{x \left (\frac{a x + b}{x}\right )^{n}}{d^{2} x^{2} + 2 \, c d x + c^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a + \frac{b}{x}\right )}^{n} x}{{\left (d x + c\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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